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3x^2-4x-4.4=0
a = 3; b = -4; c = -4.4;
Δ = b2-4ac
Δ = -42-4·3·(-4.4)
Δ = 68.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-\sqrt{68.8}}{2*3}=\frac{4-\sqrt{68.8}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+\sqrt{68.8}}{2*3}=\frac{4+\sqrt{68.8}}{6} $
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